Hi,
I encoded a movie with 591,952 quot;kbytesquot; as target size and it came out 603,056,769 bytes (Matroska) which would be
603,057 kbytes (1 kbyte = 1,000 byte) -gt; 11,105 kbytes too high
588,923 Kbytes (1 Kbyte = 1,024 byte) -gt; 3,029 Kbytes too low
So is it actually kbytes or Kbytes you have to specify?
And another question: should the XviD (no audio) be encoded to Matroska or AVI? I notice opening Matroska Files with VirtualDubMod takes a little time, and I need to open it in order to mux the audio in.
BTW I just saw an error message stating quot;Warning: Nothing To Output, BFrame Decoder Lagquot; in the first frame, is that something to worry about?
When converting the film from Matroska to AVI, the AVI ends up at 605,272,064 bytes
605,272 kbytes -gt; 13,320 kbytes too high
591,086 Kbytes -gt; 866 Kbytes too low
It seems XviD is measuring in KBytes and takes the AVI overhead into consideration. Can anyone confirm this? I don't want to draw my conclusions from just one single encode.
I'm new to XviD and Matroska, sorry if this has been asked before, I could not find anything about it.
TIA
EDIT: Assuming target size in XviD is measured in Kbytes = 1,024 Bytes do these formulas for calculating the target size make sense?when audio encoding is already done:
target size = (700 * 1,024) - ((audio in bytes) / 1,024)
700 * 1,024 = 716,800 is the capacity of a CDR in Kbyte
/ 1,024 converts the audio filesize from byte to Kbyte
Note that by quot;1,024quot; I mean quot;1024quot; i.e. 2^10when audio encoding has not yet been done:
target size = (700 * 1,024) - (seconds * (audio in kbit/s) / 8.192)
/ 8.192 converts the audio rate from kbit/s to Kbyte/s
Note that by quot;8.192quot; I mean quot;8192/1000quot; i.e. a rational number between 8 and 9.Do you agree with these formulas? |
Post at 2011-4-15 16:38
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