Bitrate question when make vobs fit on a DVD+/-R following, question, average, minimum

andy

Hi!

I hope I can get som help with this question. I'm encoding a DVD (Stargate) and trying to make it fit on a DVD+/-R.
I'm having a problem when I'm following the guide here at Doom9 when it comes to what bitrate, in TMPGEnc, I'm suppose to use.
According to the guide I'm suppose to choose the maximum bitrate of 9800 minus the total of all my audio files (which is one and it has 448kbps) this would end up at 9352. The minimum is suppose to be 0. Then we come to the problem, the average bitrate, for thiss I use DVD-R Calulator. I load my cffl file in ReMPEG2 to get my movie length and the avg bitrate. I put these values (extras: 298725376, vobs: 5739655168, length: 7804.5 and avg. bitrate: 5330000) into
DVD-R Calculator. I end up with the values (Size of video: 5199748125, size of audio: 539907043, size of new video: 3853619352, scalefactor: 74,11). To get the average bitrate for TMPG the guide says to take size of new video divided by 8 times the length of the movie in seconds (3853619352/(8*7804,5)=61721,11205) Which is way to high, well I thought maby that is in bit/sec and I need it in kbit/s in TMPG, but if I take 61721/1000 I end up with 61.721 which is way to small.
What am I doing wrong here, can someone help me please. I would like this top work and I don't know what I'm doing wrong.

Thanks in advance y'all

[size of file (Bytes)]/[length of file (seconds)]= [avg. bitrate(Bytes/sec)]

[avg.bitrate (bits/sec)]=8*[avg.bitrate(Bytes/sec)]

in your case you would have 3950151.17 bits/secPS you had that 8 factor in the wrong place. You have to multiply the size in Bytes by 8 to get the size in bits, then you divide by the file length.

thanks a lot man